Question

Answer 1

a, \(R_{td}=R_1+R_2=15+24=39\left(\Omega\right)\)

b, \(U_1=2,5.15=37,5\left(V\right)\)

\(U_2=2,5.24=60\left(V\right)\)

\(U=U_1+U_2=97,5\left(V\right)\)

c, ta có \(\dfrac{U}{R_1+R_2+R_3}=2\)

\(\Leftrightarrow\dfrac{97,5}{15+24+R_3}=2\Rightarrow R_3=7,75\left(\Omega\right)\)

Answer 2

a,\(R1ntR2=>Rtd=R1+R2=15+24=39\left(om\right)\)

b,\(=>Uab=Im.Rtd=2,5.39=97,5V\)

\(=>Im=I1=I2=2,5A=>U1=I1.R1=15.2,5=37,5V\)

\(=>U2=Uab-U1=97,5-37,5=60V\)

c, chưa chụp hết đề