Question

Answer 1

a) \(\dfrac{3}{7}+\dfrac{1}{2}-\dfrac{17}{7}+\dfrac{3}{2}\\ =\left(\dfrac{3}{7}-\dfrac{17}{7}\right)+\left(\dfrac{1}{2}+\dfrac{3}{2}\right)\\ =-2+2=0\)

b) \(\dfrac{1}{7}+\dfrac{6}{7}.\left(\dfrac{1}{2}-\dfrac{1}{3}\right)\\ =\dfrac{1}{7}+\dfrac{6}{7}.\dfrac{1}{6}=\dfrac{1}{7}+\dfrac{1}{7}\\ =\dfrac{2}{7}\)

c) \(\left(-2\right)^3+\left(75\%-0,25\right):\left(2\dfrac{1}{4}-1\dfrac{5}{6}\right)+\left(0,125\right)^3.8^3\\ =\left(-2\right)^3+\dfrac{1}{2}:\left(\dfrac{9}{4}-\dfrac{11}{6}\right)+\left(0,125.8\right)^3\\ =-8+\dfrac{1}{2}:\dfrac{5}{12}+1\\ =-8+\dfrac{1}{2}.\dfrac{12}{5}+1\\ =-\dfrac{29}{5}\)