Bài đấy nhầm
Ta có: \(\dfrac{4x}{12}+\dfrac{3x+7}{6}=\dfrac{6-2x}{3}+\dfrac{7-x}{4}\)
\(\dfrac{4x}{12}+\dfrac{6x+14}{12}=\dfrac{24-8x}{12}+\dfrac{21-3x}{12}\)
\(\dfrac{10x+14}{12}=\dfrac{45-11x}{12}\)
\(10x+14=45-11x\)
\(10x+14+11x=45\)
\(21x+14=45\)
\(21x=45-14\)
\(21x=31\)
\(x=\dfrac{31}{21}\)
