Question

Answer 1

\(\dfrac{6}{x+2}=\dfrac{3}{x-2}+\dfrac{12}{2x-4}\)(ĐKXĐ: x≠2; x≠-2)

⇔\(\dfrac{12\left(x-2\right)}{2\left(x-2\right)\left(x+2\right)}=\dfrac{6\left(x+2\right)}{2\left(x-2\right)\left(x+2\right)}+\dfrac{12\left(x+2\right)}{2\left(x-2\right)\left(x+2\right)}\)

⇔\(\dfrac{12\left(x-2\right)-6\left(x+2\right)-12\left(x+2\right)}{2\left(x-2\right)\left(x+2\right)}=0\)

⇒\(12x-24-6x-12-12x-24=0\)

⇔\(-6x-60=0\)

⇔\(x=-10\)(thỏa mãn ĐKXĐ)

vậy.....

Answer 2

biểu thức cuối là \((x)^{2}\) hay là x.2

Answer 3

\(\dfrac{6}{x+2}=\dfrac{3}{x-2}+\dfrac{12}{2x-4}\)

\(\dfrac{6}{x+2}=\dfrac{3}{x-2}+\dfrac{12}{2\left(x-2\right)}\)

\(\dfrac{6}{x+2}=\dfrac{3}{x-2}+\dfrac{6}{x-2}\)

\(\dfrac{6}{x+2}=\dfrac{3+6}{x-2}\)

\(\dfrac{6}{x+2}=\dfrac{9}{x-2}\)

\(6\left(x-2\right)=9\left(x+2\right)\)

\(6x-12=9x+18\)

\(6x-9x=12+18\)

\(-3x=30\)

\(x=30\div\left(-3\right)\)

x=-10