Question

Answer 1

 theo ta thấy \(\dfrac{R1}{R3}\ne\dfrac{R2}{R4}\)=>mạch ko cân bằng

=>chuyển mạch sao

\(=>x=\dfrac{R2.R5}{R4+R2+R5}=\dfrac{2.3}{2+3+5}=0,6\left(om\right)\)

\(=>y=\dfrac{R2.R4}{R2+r4+R5}=\dfrac{2.5}{2+5+3}=1\left(om\right)\)

\(=>z=\dfrac{R4.R5}{R4+R5+R2}=\dfrac{5.3}{3+5+2}=1,5\left(om\right)\)

\(=>Rtd=\dfrac{\left(R1+Rx\right)\left(R3+z\right)}{R1+Rx+R3+Rz}+Ry=\dfrac{\left(3+0,6\right)\left(3+1,5\right)}{3+0,6+3+1,5}+1\)\(=3\left(om\right)\)