b: ĐKXĐ: cosx<>0
=>\(x<>\frac{\pi}{2}+k\)
Ta có; \(4\cdot\tan^2x-\frac{4}{cosx}+5=0\)
=>\(4\left(\frac{1}{cos^2x}-1\right)-\frac{4}{cosx}+5=0\)
=>\(\frac{4}{cos^2x}-\frac{4}{cosx}+1=0\)
=>\(\left(\frac{2}{cosx}-1\right)^2=0\)
=>\(\frac{2}{cosx}-1=0\)
=>cosx=2(vô lý)
=>x∈∅




