PTHH em tự viết nhé !
\(304.\)
\(V_{C_2H_5OH}=0.08\cdot1=0.08\left(l\right)=80\left(ml\right)\)
\(n_{C_2H_5OH}=\dfrac{80\cdot0.8}{46}=\dfrac{32}{23}\left(mol\right)\)
\(n_{CH_3COOH\left(bđ\right)}=\dfrac{32}{23}:92\%=\dfrac{800}{529}\left(mol\right)\)
\(m=90.8\left(g\right)\)
\(304.C_2H_5OH+O_2\underrightarrow{\text{men giấm}}CH_3COOH+H_2O\)
\(305.\)
\(\left(C_6H_{10}O_5\right)_n\underrightarrow{^{85\%}}nC_6H_{12}O_6\underrightarrow{^{80\%}}2nCH_3CH\left(OH\right)COOH\)
\(H=0.85\cdot0.8=0.68\)
\(\left(C_6H_{10}O_5\right)_n\underrightarrow{^{68\%}}2nCH_3CH\left(OH\right)COOH\)
\(162n.............2n\cdot90\)
\(m=\dfrac{13.5\cdot162}{2\cdot90\cdot0.68}=17.87\left(g\right)\)
