\(n_{CO_2}=0.3\left(mol\right)\)
\(n_{H_2O}=0.3\left(mol\right)\)
\(n_X=\dfrac{0.3}{n}\left(mol\right)\)
\(M=\dfrac{7.4}{\dfrac{0.3}{n}}=\dfrac{74}{3}m\left(\dfrac{g}{mol}\right)\)
\(\Leftrightarrow14n+32=\dfrac{74}{3}n\)
\(\Leftrightarrow n=3\)
\(CT:C_3H_6O_2\)
Có 3 CT thỏa mãn
