Question

Answer 1

- Ta có : \(\left\{{}\begin{matrix}n_{Ba\left(OH\right)2}=C_M.V=0,05\left(mol\right)\\n_{KOH}=C_M.V=0,05\left(mol\right)\end{matrix}\right.\)

\(\Rightarrow n_{OH^-}=2n_{Ba\left(OH\right)2}+n_{KOH}=0,15\left(mol\right)\)

Ta có : \(V_{dds}=V_{Ba\left(OH\right)2}+V_{KOH}=200\left(ml\right)=0,2\left(l\right)\)

\(\Rightarrow C_{MOH^-}=\dfrac{n}{V}=0,75M\)