a,b dễ bn tự làm
c,\(2x-3=x+\dfrac{1}{2}\)
\(2x-3-\dfrac{1}{2}=x\)
\(2x-\dfrac{7}{2}=x\)
⇒\(x=\dfrac{7}{2}\)
d,\(4x-\left(2x+1\right)=3-\dfrac{1}{3}+x\)
\(4x-2x-1=3-\dfrac{1}{3}+x\)
\(2x-1=\dfrac{8}{3}+x\)
\(2x-1-x=\dfrac{8}{3}\)
\(x-1=\dfrac{8}{3}\)
\(x=\dfrac{8}{3}+1\)
\(x=\dfrac{11}{3}\)
a,\(\dfrac{17}{6}-\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}< =>-x+\dfrac{7}{6}=\dfrac{7}{4}-\dfrac{17}{6}\)
\(< =>-x+\dfrac{7}{6}=-\dfrac{13}{12}< =>-x=-\dfrac{9}{4}< =>x=\dfrac{9}{4}\)
b,\(\dfrac{4}{3}+\left(1,25-x\right)=2,25< =>1,25-x=2,25-\dfrac{4}{3}\)
\(< =>1,25-x=\dfrac{11}{12}< =>-x=-\dfrac{1}{3}< =>x=\dfrac{1}{3}\)
Giải:
a) \(\dfrac{17}{6}-\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}\)
\(x-\dfrac{7}{6}=\dfrac{17}{6}-\dfrac{7}{4}\)
\(x-\dfrac{7}{6}=\dfrac{13}{12}\)
\(x=\dfrac{13}{12}+\dfrac{7}{6}\)
\(x=\dfrac{9}{4}\)
b) \(\dfrac{4}{3}+\left(1,25-x\right)=2,25\)
\(\dfrac{5}{4}-x=\dfrac{9}{4}-\dfrac{4}{3}\)
\(\dfrac{5}{4}-x=\dfrac{11}{12}\)
\(x=\dfrac{5}{4}-\dfrac{11}{12}\)
\(x=\dfrac{1}{3}\)
c) \(2x-3=x+\dfrac{1}{2}\)
\(\Rightarrow2x-x=\dfrac{1}{2}+3\)
\(\Rightarrow x=\dfrac{7}{2}\)
d) \(4x-\left(2x+1\right)=3-\dfrac{1}{3}+x\)
\(\Rightarrow4x-2x-1=3-\dfrac{1}{3}+x\)
\(\Rightarrow4x-2x-x=3-\dfrac{1}{3}+1\)
\(\Rightarrow x=\dfrac{11}{3}\)
