Bài 5:
a,\(AB=OB-OA=5-2=3\left(cm\right)\)
\(BC=OB +OC=5+1=6\left(cm\right)\)
b,\(AC=OA+OC=2+1=3\left(cm\right)\)
\(AB=3cm=AC\)
\(\Rightarrow A\) là đường trung trực BC
c, \(AM=\dfrac{1}{2}AB=\dfrac{3}{2}\left(cm\right)\)
\(OM=OA+AM=1+\dfrac{3}{2}=\dfrac{5}{2}\left(cm\right)\)
Bài 6:
b,\(A=10^{30}\) và \(B=2^{100}\)
\(A=10^{30}=10^{3.10}=\left(10^3\right)^{10}=1000^{10}\)
\(B=2^{100}=2^{10.10}=\left(2^{10}\right)^{10}=\left(1024\right)^{10}\)
Do \(1000^{10}< 1024^{10}\Rightarrow A< B\)
-Chúc bạn học tốt-
6
a, 2A = 2 ( 20+21+22+...+22014)
=> 2A - A = ( 21+22+23+...+22015) - ( 20+21+22+...+22014)
=> A = 22015 - 20
=> A = 22015 - 1
=> A=B
b,
1030= 2150
=> C>D
