Bài 11 :
a) P(x) = \(5x^3-3x+7-x=5x^3-4x+7\)
Q(x) = \(-5x^3+2x-3+2x-x^2-2=-5x^3+4x-x^2-5\)
b) M(x) = P(x) + Q(x)
= \(\left(5x^3-4x+7\right)+\left(-5x^3+4x-x^2-5\right)\)
= \(5x^3-4x+7-5x^3+4x-x^2-5\)
= \(2-x^2\)
c) Ta có : M(x) = 0
⇔ \(2-x^2=0\)
⇔ \(-x^2=-2\)
⇔ \(\left[{}\begin{matrix}x=\sqrt{2}\\x=-\sqrt{2}\end{matrix}\right.\)
