Bài 2
a,\(\dfrac{2}{3}\)x-\(\dfrac{1}{3}\)=\(\dfrac{1}{2}\)-\(\dfrac{2}{3}\)
\(\dfrac{2}{3}\)x-\(\dfrac{1}{3}\)=\(\dfrac{-1}{6}\)
\(\dfrac{2}{3}\)x=\(\dfrac{-1}{6}\)+\(\dfrac{1}{3}\)
\(\dfrac{2}{3}\)x=\(\dfrac{1}{6}\)
x=\(\dfrac{1}{6}\):\(\dfrac{2}{3}\)
x=\(\dfrac{1}{4}\)
b,\(\dfrac{3}{x+5}\)=\(\dfrac{3}{20}\)
⇒x+5=20
x=20-5
x=15
Giải:
a) \(\dfrac{1}{2}-\left(\dfrac{2}{3}x-\dfrac{1}{3}\right)=\dfrac{2}{3}\)
\(\dfrac{2}{3}x-\dfrac{1}{3}=\dfrac{1}{2}-\dfrac{2}{3}\)
\(\dfrac{2}{3}x-\dfrac{1}{3}=\dfrac{-1}{6}\)
\(\dfrac{2}{3}x=\dfrac{-1}{6}+\dfrac{1}{3}\)
\(\dfrac{2}{3}x=\dfrac{1}{6}\)
\(x=\dfrac{1}{6}:\dfrac{2}{3}\)
\(x=\dfrac{1}{4}\)
b) \(\dfrac{3}{x+5}=15\%\)
\(\dfrac{3}{x+5}=\dfrac{3}{20}\)
\(\Rightarrow x+5=20\)
\(x=20-5\)
\(x=15\)
Chúc bạn học tốt!
Bài 2:
a) \(\dfrac{1}{2}\)-\(\left(\dfrac{2}{3}x-\dfrac{1}{3}\right)\)=\(\dfrac{2}{3}\)
\(\left(\dfrac{2}{3}x-\dfrac{1}{3}\right)\) =\(\dfrac{1}{2}\)-\(\dfrac{2}{3}\)
\(\left(\dfrac{2}{3}x-\dfrac{1}{3}\right)\)=\(\dfrac{-1}{6}\)
\(\dfrac{2}{3}x\) = \(\dfrac{-1}{6}\)+\(\dfrac{1}{3}\)
\(\dfrac{2}{3}x\) = \(\dfrac{1}{6}\)
\(x\) = \(\dfrac{1}{6}\):\(\dfrac{2}{3}\)
\(x\) = \(\dfrac{1}{4}\)
b)
\(\dfrac{3}{x+5}\)=\(\dfrac{3}{20}\)
⇒x+5=20
x=20-5
x=15
