\(\dfrac{x^2-10x-29}{1971}+\dfrac{x^2-10x-27}{1973}=\dfrac{x^2-10x-1971}{29}+\dfrac{x^2-10x-1973}{27}\)
\(\Leftrightarrow\left(\dfrac{x^2-10x-29}{1971}-1\right)+\left(\dfrac{x^2-10x-27}{1973}-1\right)=\left(\dfrac{x^2-10x-1971}{29}-1\right)+\left(\dfrac{x^2-10x-1973}{27}-1\right)\)
\(\Leftrightarrow x^2-10x-2000=0\)
\(\Leftrightarrow x^2-10x+25-2025=0\)
\(\Leftrightarrow\left(x-5\right)^2=2025\)
=>x-5=45 hoặc x-5=-45
=>x=50 hoặc x=-40
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