\(\left(x-5\right)\left(x-6\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0+5\\x=0+6\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=5\\x=6\end{array}\right.\)
\(\left(x-5\right).\left(x-6\right)=0\)
Tại đây sẽ có hai trường hợp xảy ra :
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-5=0\\x-6=0\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0+5\\x=0+6\end{array}\right.\Leftrightarrow\left[\begin{array}{nghiempt}x=5\\x=6\end{array}\right.\)
Vậy \(x\in\left\{5;6\right\}\) thõa mãn
\(\left(x-5\right).\left(x-6\right)=0\)
ta xét 2 trường hợp:
<=>\(\left[\begin{array}{nghiempt}x-5=0\\x-6=0\end{array}\right.\)
<=>\(\left[\begin{array}{nghiempt}x=0+5\\x=0+6\end{array}\right.\)<=>\(\left[\begin{array}{nghiempt}x=5\\x=6\end{array}\right.\)
vậy \(x\in\left\{5,6\right\}\) thỏa mãn
\(\left(x-5\right).\left(x-6\right)=0\)
\(\Rightarrow x-5=0\) hoặc \(x-6=0\)
+) \(x-5=0\Rightarrow x=5\)
+) \(x-6=0\Rightarrow x=6\)
Vậy \(x=5\) hoặc \(x=6\)