Question

Tìm x :

\(\left(x+3\right).\left(x+4\right).\left(x+5\right).\left(x+6\right)=0\)

Answer 1

\(\left(x+3\right).\left(x+4\right).\left(x+5\right).\left(x+6\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x+3=0\\x+4=0\\x+5=0\\x+6=0\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=0-3\\x=0-4\\x=0-5\\x=0-6\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-3\\x=-4\\x=-5\\x=-6\end{array}\right.\)

Vậy \(x\in\left\{-3;-4;-5;-6\right\}\)

Answer 2

\(\left(x+4\right)\left(x+4\right)\left(x+5\right)\left(x+6\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x+3=0\\x+4=0\\x+5=0\\x+6=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-3\\x=-4\\x=-5\\x=-6\end{array}\right.\)

Vậy \(x\in\left\{-3;-4;-5;-6\right\}\)

Answer 3

\(\left(x+3\right)\left(x+4\right)\left(x+5\right)\left(x+6\right)=0\)

TH1: \(x+3=0\Rightarrow x=-3\)

TH2: \(x+4=0\Rightarrow x=-4\)

TH3: \(x+5=0\Rightarrow x=-5\)

TH4: \(x+6=0\Rightarrow x=-6\)

Vậy: \(x=-3\) hoặc \(x=-4\) hoặc \(x=-5\) hoặc \(x=-6\)

Answer 4

(x+3).(x+4).(x+5).(x+6)=0

TH1: x + 3 = 0 => x = 0 - 3 = -3

TH2: x + 4 =0 =>  x = 0 - 4 = -4

TH3: x + 5 = 0 => x= 0 - 5 = -5 

TH4: x + 6 = 0 => x= 0 -6 = -6

                               OK