\(\left(x+5\right)\left(x-2\right)\left(x+4\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+5=0\\x-2=0\\x+4=0\\x+3=0\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-5\\x=2\\x=-4\\x=-3\end{array}\right.\)
Vậy \(x\in\left\{-5;2;-4;-3\right\}\)
\(\left(x+5\right)\left(x-2\right)\left(x+4\right)\left(x+3\right)=0\)
\(\Rightarrow\left[\begin{array}{nghiempt}x+5=0\\x-2=0\\x+4=0\\x+3=0\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=0-5\\x=2+0\\x=0-4\\x=0-3\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=-5\\x=2\\x=-4\\x=-3\end{array}\right.\)
có (x+5)(x-2) ( x+4)(x+3) = 0
=> x+5 = 0=> x= -5
hoặc x-2=0 => x= 2
hoặc x+4=0 => x= -4
hoặc x+3 =0=> x=-3
vậy x thuộc { -5;2;-4;-3}
Th1 : x = -5
Th2 : x= 2
Th3 : x = -4
Th4 : x= -3 
