Chia 2 trường hợp:
TH 1: \(\sqrt{3x+2}-\sqrt{2y-1}=0\)
\(\Leftrightarrow y=\dfrac{3x+3}{2}\)
\(\Rightarrow\dfrac{5x}{3}-\dfrac{3x+3}{2}=0\)
\(\Leftrightarrow x=9\)
\(\Rightarrow y=15\)
TH 2: \(\left\{{}\begin{matrix}3x+2=a^2\\2y-1=b^2\end{matrix}\right.\)
Tự làm nốt nhé