\(A=\left|x-2013\right|+\left|2014-x\right|+\left|x-2015\right|\)
\(\Rightarrow A=\left|x-2013\right|+\left|x-2014\right|+\left|2015-x\right|\)
\(\Rightarrow A\ge\left|x-2013+0+2015-x\right|\)
\(\Rightarrow A\ge2.\)
Dấu '' = '' xảy ra khi:
\(\left\{{}\begin{matrix}x-2013\ge0\\2014-x=0\\x-2015\le0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x\ge2013\\x=2014\\x\le2015\end{matrix}\right.\Rightarrow x=2014.\)
Vậy \(MIN_A=2\) khi \(x=2014.\)
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