Question

Rút gọn biểu thức

\(\dfrac{\sqrt{x^2-4x+4}}{x-2}\) với \(x\ne2\)

Answer 1

\(\dfrac{\sqrt{x^2-4x+4}}{x-2}=\dfrac{\left|x-2\right|}{x-2}=\left[{}\begin{matrix}1\left(x\ge2\right)\\-1\left(x< 2\right)\end{matrix}\right.\)

 

Answer 2

\(\dfrac{\sqrt{x^2-4x+4}}{x-2}=\dfrac{\left|x-2\right|}{x-2}=\pm1\)