Question

Phân thức đa thức thành nhân tử:

x²y-x³-16y+16x

Answer 1

\(x^2y-x^3-16y+16x=\left(x^2y-x^3\right)-\left(16y-16x\right)=x^2\left(y-x\right)-16\left(y-x\right)=\left(x^2-16\right)\left(y-x\right)=\left(x-4\right)\left(x+4\right)\left(y-x\right)\)

Answer 2

\(x^2y-x^3-16y+16x=-x^2\left(x-y\right)+16\left(x-y\right)=\left(x-y\right)\left(16-x^2\right)=\left(x-y\right)\left(4-x\right)\left(4+x\right)\)

Answer 3

Ta có: \(x^2y-x^3+16x-16y\)

\(=x^2\left(y-x\right)-\left(y-x\right)\)

\(=\left(y-x\right)\left(x-1\right)\left(x+1\right)\)