Question

Giúp mk câu này !

Answer 1

hello chị

Answer 2

ĐKXĐ: \(x\ge\dfrac{5}{2}\)

\(\sqrt{2x-4+2\sqrt{2x-5}}+\sqrt{2x+4+6\sqrt{2x-5}}=14\)

\(\Leftrightarrow\sqrt{2x-5+2\sqrt{2x-5}+1}+\sqrt{2x-5+6\sqrt{2x-5}+9}=14\)

\(\Leftrightarrow\sqrt{\left(\sqrt{2x-5}+1\right)^2}+\sqrt{\left(\sqrt{2x-5}+3\right)^2}=14\)

\(\Leftrightarrow\sqrt{2x-5}+1+\sqrt{2x-5}+3=14\)

\(\Leftrightarrow\sqrt{2x-5}=5\)

\(\Leftrightarrow x=15\)