Câu 3:
\(a,\dfrac{a}{2}=\dfrac{b}{5}=\dfrac{a-b}{2-5}=\dfrac{9}{-3}=-3\\ \Rightarrow\left\{{}\begin{matrix}a=-6\\b=-15\end{matrix}\right.\\ b,\dfrac{a}{3}=\dfrac{b}{6}=\dfrac{a-b}{3-6}=\dfrac{12}{-3}=-4\\ \Rightarrow\left\{{}\begin{matrix}a=-12\\b=-24\end{matrix}\right.\\ c,\dfrac{a}{4}=\dfrac{b}{5}=\dfrac{a-2b}{4-10}=\dfrac{-30}{-6}=5\\ \Rightarrow\left\{{}\begin{matrix}a=20\\b=25\end{matrix}\right.\)
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