\(sin2x-cos2x+3sinx-cosx-1=0\)
\(\Leftrightarrow2sinxcosx-\left(1-2sin^2x\right)+3sinx-cosx-1=0\)
\(\Leftrightarrow2sinxcosx-1+2sin^2x+3sinx-cosx-1=0\)
\(\Leftrightarrow2sin^2x+3sinx-2+cosx\left(2sinx-1\right)=0\)
\(\Leftrightarrow2\left(sinx-\dfrac{1}{2}\right)\left(sinx+2\right)+cosx\left(2sinx-1\right)=0\)
\(\Leftrightarrow\left(2sinx-1\right)\left(sinx+2\right)+cosx\left(2sinx-1\right)=0\)
\(\Leftrightarrow\left(2sinx-1\right)\left(sinx+2+cosx\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}2sinx-1=0\\sinx+cosx+2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}sinx=\dfrac{1}{2}\\sinx+cosx=-2\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}sinx=sin\dfrac{\pi}{6}\\\sqrt[]{2}\left(sinx.\dfrac{1}{\sqrt[]{2}}+cosx.\dfrac{1}{\sqrt[]{2}}\right)=-2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\pi}{6}+k2\pi\\x=\dfrac{5\pi}{6}+k2\pi\\\sqrt[]{2}sin\left(x+\dfrac{\pi}{4}\right)=-2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\pi}{6}+k2\pi\\x=\dfrac{5\pi}{6}+k2\pi\\sin\left(x+\dfrac{\pi}{4}\right)=-\sqrt[]{2}\left(vô.lý\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{\pi}{6}+k2\pi\\x=\dfrac{5\pi}{6}+k2\pi\end{matrix}\right.\) \(\left(k\in Z\right)\)
