Question

Giải phương trình sau

\(\sqrt{x^2+1}=5\)

Answer 1

\(\sqrt{x^2+1}=5\)

<=> x + 1 = 25

<=> x = 25 - 1

<=> x = 24

Answer 2

\(\sqrt{x^2+1}=5\)

\(\Leftrightarrow x^2+1=25\)

hay \(x\in\left\{2\sqrt{6};-2\sqrt{6}\right\}\)

Answer 3

\(PT\Leftrightarrow x^2+1=25\Leftrightarrow x^2=24\\ \Leftrightarrow\left[{}\begin{matrix}x=2\sqrt{6}\\x=-2\sqrt{6}\end{matrix}\right.\)

Answer 4

Sorry, mik sai đề