x^2+2x-2=0
=>x^2+2x+1-3=0
=>(x+1)^2=3
=>\(\left[{}\begin{matrix}x=-\sqrt{3}-1\\x=\sqrt{3}-1\end{matrix}\right.\)
TH1: \(x=-\sqrt{3}-1\)
\(M=\left(-\sqrt{3}-1\right)^4+16\left(-\sqrt{3}-1\right)+2007\)
\(=\left(4+2\sqrt{3}\right)^2-16\sqrt{3}-16+2007\)
\(=28+16\sqrt{3}-16\sqrt{3}+1991=2019\)
TH2: \(x=\sqrt{3}-1\)
\(M=\left(4-2\sqrt{3}\right)^2+16\left(\sqrt{3}-1\right)+2007\)
\(=28-16\sqrt{3}+16\sqrt{3}-16+2007=2019\)