\(M=\frac{x^2-2x}{2-x}\)
a/ ĐKXĐ: \(2-x\ne0\Leftrightarrow x\ne2\)
b/ Với $x \ne 2$, \(M=0\Leftrightarrow\frac{x^2-2x}{2-x}=0\Leftrightarrow x^2-2x=0\Leftrightarrow x\left(x-2\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=2\left(loai\right)\end{matrix}\right.\)
KL: Vậy \(x=2\) thì $M=0$