Bài 2: Căn thức bậc hai và hằng đẳng thức căn bậc hai của bình phương
Các câu hỏi tương tự
Tính:a) left(sqrt{1dfrac{9}{16}}-sqrt{dfrac{9}{16}}right):5b) left(sqrt{3}-2right)^2left(sqrt{3}+2right)^2c) left(11-4sqrt{3}right)left(11+4sqrt{3}right)d) left(sqrt{2}-1right)^2-dfrac{3}{2}sqrt{left(-2right)^2}+dfrac{4sqrt{2}}{5}+sqrt{1dfrac{11}{25}}.sqrt{2}e) left(1+sqrt{2021}right)sqrt{2022-2sqrt{2021}}
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Tính:
a) \(\left(\sqrt{1\dfrac{9}{16}}-\sqrt{\dfrac{9}{16}}\right):5\)
b) \(\left(\sqrt{3}-2\right)^2\left(\sqrt{3}+2\right)^2\)
c) \(\left(11-4\sqrt{3}\right)\left(11+4\sqrt{3}\right)\)
d) \(\left(\sqrt{2}-1\right)^2-\dfrac{3}{2}\sqrt{\left(-2\right)^2}+\dfrac{4\sqrt{2}}{5}+\sqrt{1\dfrac{11}{25}}.\sqrt{2}\)
e) \(\left(1+\sqrt{2021}\right)\sqrt{2022-2\sqrt{2021}}\)
1.Thu gọn
A=\(\dfrac{1}{\sqrt{2}+\sqrt{3}}+\dfrac{1}{\sqrt{3}+\sqrt{4}}+\dfrac{1}{\sqrt{4}+\sqrt{5}}+...+\dfrac{1}{\sqrt{2020}+\sqrt{2021}}\)
\(a,2\sqrt{20}-\sqrt{50}+3\sqrt{80}-\sqrt{320}\)
\(b,\sqrt{32}-\sqrt{50}+\sqrt{18}\)
\(c,3\sqrt{3}+4\sqrt{2}-5\sqrt{27}\)
\(d,\dfrac{\sqrt{3}}{\sqrt{\sqrt{3}+1}-1}-\dfrac{\sqrt{3}}{\sqrt{\sqrt{3}+1}+1}\)
e,\(\left(2+\dfrac{3+\sqrt{3}}{\sqrt{3}+1}\right)\left(2-\dfrac{3-\sqrt{3}}{\sqrt{3}-1}\right)\)
1.\(\sqrt{-4x^2+25}=x\)
2.\(\sqrt{3x^2-4x+3}=1-2x\)
3. \(\sqrt{4\left(1-x\right)^2}-\sqrt{3}=0\)
4.\(\dfrac{3\sqrt{x+5}}{\sqrt{ }x-1}< 0\)
5. \(\dfrac{3\sqrt{x-5}}{\sqrt{x+1}}\ge0\)
Tính:
\(\left(\dfrac{3\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}+\dfrac{3\sqrt{2}+2\sqrt{3}}{\sqrt{3}+\sqrt{2}}\right)\cdot\dfrac{5-2\sqrt{6}}{4}\)
tính:
a,\(\sqrt{9-4\sqrt{5}}-\sqrt{5}\)
b,\(\sqrt{7-4\sqrt{3}}+\sqrt{4-2\sqrt{3}}\)
c,\(\dfrac{x-49}{\sqrt{x}-7}\)
d,\(\sqrt{4+2\sqrt{3}}-\sqrt{13+4\sqrt{3}}\)
e,\(2+\sqrt{17-4\sqrt{9+4\sqrt{45}}}\)
Bài 1 :
a, dfrac{1}{2}sqrt{12}+sqrt{27}-sqrt{75}
b, sqrt{7-4sqrt{3}}-sqrt{4+2sqrt{3}}
c, 6sqrt{27}-2sqrt{75}-dfrac{1}{2}sqrt{300}
d, dfrac{7}{sqrt{10}-sqrt{3}}-dfrac{5sqrt{2}-2sqrt{5}}{sqrt{5}-sqrt{2}}-dfrac{6}{sqrt{3}}
e, sqrt{dfrac{sqrt{5}}{8sqrt{5}+3sqrt{35}}}.(3sqrt{2}+sqrt{14)}
f, sqrt{11-4sqrt{ }7}+dfrac{2sqrt{7}-2}{sqrt{7}-1}
g, (sqrt{125}-3sqrt{3})dfrac{sqrt{5}-sqrt{3}}{8+sqrt{15}}
h, sqrt{100}-sqrt{64}
i, sqrt{(1-sqrt{3})^2}-sqrt{3}
Bạn nào biết làm bài này thì giúp mình với...
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Bài 1 :
a, \(\dfrac{1}{2}\sqrt{12}+\sqrt{27}-\sqrt{75}\)
b, \(\sqrt{7-4\sqrt{3}}-\sqrt{4+2\sqrt{3}}\)
c, 6\(\sqrt{27}-2\sqrt{75}-\dfrac{1}{2}\sqrt{300}\)
d, \(\dfrac{7}{\sqrt{10}-\sqrt{3}}-\dfrac{5\sqrt{2}-2\sqrt{5}}{\sqrt{5}-\sqrt{2}}-\dfrac{6}{\sqrt{3}}\)
e, \(\sqrt{\dfrac{\sqrt{5}}{8\sqrt{5}+3\sqrt{35}}}.(3\sqrt{2}+\sqrt{14)}\)
f, \(\sqrt{11-4\sqrt{ }7}+\dfrac{2\sqrt{7}-2}{\sqrt{7}-1}\)
g, \((\sqrt{125}-3\sqrt{3})\dfrac{\sqrt{5}-\sqrt{3}}{8+\sqrt{15}}\)
h, \(\sqrt{100}-\sqrt{64}\)
i, \(\sqrt{(1-\sqrt{3})^2}-\sqrt{3}\)
Bạn nào biết làm bài này thì giúp mình với ạ ! sáng mai mình cần gấp !
Rút gọn:
A = \(\sqrt{\dfrac{3\sqrt{3}-4}{2\sqrt{3}+1}}+\sqrt{\dfrac{\sqrt{3}+4}{5-2\sqrt{3}}}\)
Giải các phương trình sau:a) sqrt{x^2-4+4}2-xb) sqrt{4x-8}-dfrac{1}{5}sqrt{25x-50}3sqrt{x-2}-1c) sqrt{x-1}+sqrt{9x-9}-sqrt{4x-4}4d) dfrac{1}{2}sqrt{x-2}-4sqrt{dfrac{4x-8}{9}}+sqrt{9x-18}-50e)sqrt{49-28x+4x^2}-50f) sqrt{4x-20}+sqrt{x-5}-dfrac{1}{3}sqrt{9x-45}4g) x2 - 4x - 2sqrt{2x-5}+50h)sqrt{3x-2}sqrt{x+1}i) x + y + z + 8 2sqrt{x-1}+4sqrt{y-2}+6sqrt{z-3}k) sqrt{x^2-3x}-sqrt{x-3}0l)sqrt{x^2-4}+sqrt{x-2}0m) 4sqrt{x+1}x^2-5x+14n) sqrt{x^2-6x+9}-sqrt{4x^2+4x+1}0
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Giải các phương trình sau:
a) \(\sqrt{x^2-4+4}=2-x\)
b) \(\sqrt{4x-8}-\dfrac{1}{5}\sqrt{25x-50}=3\sqrt{x-2}-1\)
c) \(\sqrt{x-1}+\sqrt{9x-9}-\sqrt{4x-4}=4\)
d) \(\dfrac{1}{2}\sqrt{x-2}-4\sqrt{\dfrac{4x-8}{9}}+\sqrt{9x-18}-5=0\)
e)\(\sqrt{49-28x+4x^2}-5=0\)
f) \(\sqrt{4x-20}+\sqrt{x-5}-\dfrac{1}{3}\sqrt{9x-45}=4\)
g) x2 - 4x - 2\(\sqrt{2x-5}+5=0\)
h)\(\sqrt{3x-2}=\sqrt{x+1}\)
i) x + y + z + 8 = \(2\sqrt{x-1}+4\sqrt{y-2}+6\sqrt{z-3}\)
k) \(\sqrt{x^2-3x}-\sqrt{x-3}=0\)
l)\(\sqrt{x^2-4}+\sqrt{x-2}=0\)
m) \(4\sqrt{x+1}=x^2-5x+14\)
n) \(\sqrt{x^2-6x+9}-\sqrt{4x^2+4x+1}=0\)