Question

Bài 1 :

a, \(\dfrac{1}{2}\sqrt{12}+\sqrt{27}-\sqrt{75}\)

b, \(\sqrt{7-4\sqrt{3}}-\sqrt{4+2\sqrt{3}}\)

c, 6\(\sqrt{27}-2\sqrt{75}-\dfrac{1}{2}\sqrt{300}\)

d, \(\dfrac{7}{\sqrt{10}-\sqrt{3}}-\dfrac{5\sqrt{2}-2\sqrt{5}}{\sqrt{5}-\sqrt{2}}-\dfrac{6}{\sqrt{3}}\)

e, \(\sqrt{\dfrac{\sqrt{5}}{8\sqrt{5}+3\sqrt{35}}}.(3\sqrt{2}+\sqrt{14)}\)

f, \(\sqrt{11-4\sqrt{ }7}+\dfrac{2\sqrt{7}-2}{\sqrt{7}-1}\)

g, \((\sqrt{125}-3\sqrt{3})\dfrac{\sqrt{5}-\sqrt{3}}{8+\sqrt{15}}\)

h, \(\sqrt{100}-\sqrt{64}\)

i, \(\sqrt{(1-\sqrt{3})^2}-\sqrt{3}\)

Bạn nào biết làm bài này thì giúp mình với ạ ! sáng mai mình cần gấp !

Answer 1

a: \(=\dfrac{1}{2}\cdot2\sqrt{3}+3\sqrt{3}-5\sqrt{3}=-\sqrt{3}\)

b: \(=2-\sqrt{3}-\sqrt{3}-1=1\)

c: \(=18\sqrt{3}-10\sqrt{3}-\dfrac{1}{2}\cdot10\sqrt{3}=3\sqrt{3}\)

d: \(=\sqrt{10}+\sqrt{3}-\sqrt{5}+\sqrt{2}-2\sqrt{3}=\sqrt{10}+\sqrt{2}-\sqrt{3}-\sqrt{5}\)