Question

\(\dfrac{x+1}{3}\)-\(\dfrac{x-3}{4}\)= 1

 

Answer 1

\(\dfrac{x+1}{3}-\dfrac{x-3}{4}=1\)

\(\dfrac{4\left(x+1\right)-3\left(x-3\right)}{12}=1\)

\(4x+4-3x+9=12\)

\(x=-1\)

Answer 2

\(\Rightarrow4x+4-3x+9=12\Leftrightarrow x=-1\)

Answer 3

\(\dfrac{x+1}{3}-\dfrac{x-3}{4}=1\\ \Leftrightarrow\dfrac{4x+4}{12}-\dfrac{3x+9}{12}=\dfrac{12}{12}\\ \Leftrightarrow4x+4-3x+9=12\\ \Leftrightarrow4x-3x=12-4-9\\ \Leftrightarrow x=-1\)

Vậy PT có tập nghiệm S = { -1 } 

Answer 4

\(\Leftrightarrow\)\(\dfrac{\left(x+1\right)4}{12}-\dfrac{\left(x-3\right)3}{12}=\dfrac{12}{12}\)

\(\Leftrightarrow\)4x+4-3x+3=12

\(\Leftrightarrow\)x+7=12

\(\Leftrightarrow\)x=5