a, \(n_{H2O}>n_{CO2}\Rightarrow CT.A:C_nH_{2n+2}O_x\left(x\le n,n\ge1\right)\)
Ta có:
\(\frac{n}{2n+2}=\frac{2}{6}\Rightarrow\frac{n}{2n+2}=\frac{1}{3}\)
\(\Rightarrow3n=2n+2\Rightarrow n=2\)
\(M_A=\frac{1}{\frac{0,487}{22,4}}=46\left(\frac{g}{mol}\right)\)
\(\Rightarrow30+16x=46\Rightarrow x=1\)
\(\Rightarrow A:C_2H_6O\)
b, \(C_2H_6O+3O_2\rightarrow2CO_2+3H_2O\)
Ta có:
\(n_{O2}=\frac{6,72}{22,4}=0,3\left(mol\right)\)
\(n_{C2H6O}=\frac{0,3}{3}=0,1\left(mol\right)\Rightarrow m=m_{C2H6O}=0,1.46=4,6\left(g\right)\)