Giả sử \(d_1\)đi qua điểm A(\(x_0,y_0\)) cố định\(\Rightarrow y_0=mx_0-x_0+1\Leftrightarrow mx_0-x_0+1-y_0=0\Leftrightarrow\left\{{}\begin{matrix}x_0=0\\-x_0+1-y_0=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x_0=0\\y_0=1\end{matrix}\right.\)
Vậy A(\(0,1\))