a: \(P=\dfrac{3x^2+9x-x-3-2x^2+2x-5x+5+4-x^2-2x+3}{\left(x+3\right)\left(x-1\right)}\)
\(=\dfrac{3x+9}{\left(x+3\right)\left(x-1\right)}=\dfrac{3}{x-1}\)
b: Khi x=1000 thì P=3/1000-1=3/999=1/333
c: A=P/x-3=3/(x-1)(x-3)
(x-1)(x-3)=x^2-4x+3=x^2-4x+4-1=(x-2)^2-1>=-1
=>A<=-3
Dấu = xảy ra khi x=2