a) A = [(2x + y) - (2x - y)] . [(2x +y) + (2x - y)]
b) B = [(x - 2y) - 2y]2
\(a,A=\left(2x+y\right)^2-\left(2x-y\right)^2\\ =\left(2x+y-2x+y\right)\left(2x+y+2x-y\right)\\ =2y\cdot4x\\ =8xy\\ b,B=\left(x-2y\right)^2-4y\left(x-2y\right)+4y^2\\ =x^2-4xy+4y^2-4xy+8y^2+4y^2\\ =x^2+16y^2-8xy\\ =\left(x-4y\right)^2\)
\(a,A=\left(2x+y\right)^2-\left(2x-y\right)^2\)
\(=\left(2x+y-2x+y\right)\left(2x+y+2x-y\right)\)
\(=2y.4x=8xy\)
Vậy \(A=8xy\)
\(----------\)
\(b,B=\left(x-2y\right)^2-4\left(x-2y\right)y+4y^2\)
\(=\left(x-2y\right)^2-2.\left(x-2y\right).2y+\left(2y\right)^2\)
\(=\left(x-2y-2y\right)^2\)
\(=\left(x-4y\right)^2\)
Vậy \(B=\left(x-4y\right)^2\)