Đặt a/b=c/d=k
=>a=bk; c=dk
a: \(\dfrac{a-b}{b}=\dfrac{bk-b}{b}=k-1\)
\(\dfrac{c-d}{d}=\dfrac{dk-d}{d}=k-1\)
Do đó: \(\dfrac{a-b}{b}=\dfrac{c-d}{d}\)
b: \(\dfrac{a}{a+b}=\dfrac{bk}{bk+b}=\dfrac{k}{k+1}\)
\(\dfrac{c}{c+d}=\dfrac{dk}{dk+d}=\dfrac{k}{k+1}\)
Do đó: \(\dfrac{a}{a+b}=\dfrac{c}{c+d}\)