Question

a. \(\sqrt{7+4\sqrt{3}}\)

b. \(\sqrt{7-2\sqrt{10}}\)

c. \(\sqrt{8+2\sqrt{15}}\)

d. \(\sqrt{12-2\sqrt{20}}\)

e.\(\sqrt{12+2\sqrt{35}}\)

Answer 1

a) \(=\left(\sqrt{3}+2\right)^2\)

b)\(=\left(\sqrt{5}-\sqrt{2}\right)^2\)

c)\(=\left(\sqrt{5}+\sqrt{3}\right)^2\)

d)\(=\left(\sqrt{10}-\sqrt{2}\right)^2\)

e) \(=\left(\sqrt{7}+\sqrt{5}\right)^2\)

Answer 2

tới đó là dễ rồi bạn tự làm tiếp nhé

Answer 3

a)\(\sqrt{2^2+2\cdot2\cdot\sqrt{3}+\left(\sqrt{3}\right)^2}=\sqrt{\left(2+\sqrt{3}\right)^2}=2+\sqrt{3}\)

b)\(\sqrt{\left(\sqrt{5}\right)^2-2\cdot\sqrt{2}\cdot\sqrt{5}+\left(\sqrt{2}\right)^2}=\sqrt{\left(\sqrt{5}-\sqrt{2}\right)^2}=\sqrt{5}-\sqrt{2}\)c)\(\sqrt{\left(\sqrt{3}\right)^2+2\cdot\sqrt{3}\cdot\sqrt{5}+\left(\sqrt{5}\right)^2}=\sqrt{\left(\sqrt{3}+\sqrt{5}\right)^2}=\sqrt{3}+\sqrt{5}\)d)\(\sqrt{\left(\sqrt{10}\right)^2-2\cdot\sqrt{2}\cdot\sqrt{10}+\left(\sqrt{2}\right)^2}=\sqrt{\left(\sqrt{10}-\sqrt{2}\right)^2}=\sqrt{10}-\sqrt{2}\)e)\(\sqrt{\left(\sqrt{5}\right)^2+2\cdot\sqrt{5}\cdot\sqrt{7}+\left(\sqrt{7}\right)^2}=\sqrt{\left(\sqrt{5}+\sqrt{7}\right)^2}=\sqrt{5}+\sqrt{7}\)