Bài 1:Phân tích đa thức thành nhân tử:
a)-8x+16x+x^2 f)(-m+2n)^2+2(2n-m)+1
b)4x^2+4y^2-8xyz g)(2p-4q)^2+4p-8q+1
c)ab^2+1/4a^2b^4+1 h)(m-n)^6-6(m-n)^4+12(m-n)^2-8
d)16u^2v^2-8uv^2+1
e)4u^4v^8+(u^2v^4)^4+4
i)(z-t)^2+15(z-t)^2+75(z-t)+125
tìm x, biết
a) (2x-1)2 -25 =0
b) (x+8)2 =121
c) x3 -4x2 +4x=0
d) 4x2 -4x=-1
1/ Phân tích đa thức thành nhân tử:
a/x^3 + 4x^2 - 29x +24
b/x^4 +6x^3 +7x^2 - 6x +1
c/(x^2 -x +2)^2 + (x-2)^2
d/6x^5 + 15x^4 + 20x^3 + 15x^2 + 6x +1
e/x^6 + 3x^5 + 4x^4 + 4x^3 + 4x^2 + 3x +1
1/ Tìm x biết:
a) 4x2 = x- \(\frac{1}{6}\) b) (2x+1).(2x- 1).(x-2).(x2 -2x+ 4)= 0
2/ Rút gọn:
a) ( 4x -2)3 - 4x.(4x+1).(4x-1)
b) 9x2 . (4- 3x)2 - ( 9x2 -1). (1+9x2)
c) 4(2x+3)2- 12(2x+3). (2-x) + 9.(x-2)2
d) 64 a3-(4a -5).(25 + 20a + 16a2 )
Tìm x, biết: a, 4x^2 - 4x = -1. b, (x-2)^2 * (5-2x)^2 = 0. c, (1-2x)^2 - (3x-2)^2 =0
tìm x
4x^2 - 4x = -1
8x^3 +12x^2 + 6x +1=0
(\(\dfrac{2x}{2x+y}\) - \(\dfrac{4x^2}{4x^2+4xy+y^2}\)) : (\(\dfrac{2x}{4x^2-y^2}\)+\(\dfrac{1}{y-2x}\))
Phân tích các đa thức sau thành nhân tử
(3x+1)^2 -4(x-2)^2
9(2x+3)^2-4(x+1)^2
(4x^2-3x-18)^2 - (4x^2+3x)^2
-4x^2+12xy-9y^2+25
9(x+y-1)^2 -4(2x+3y+1)^2
1). \(4x^2+4x+1\)
2). \(9x^2-24xy+16y^2\)
3). \(-x^2+10x-25\)
4). \(1+12x+36x^2\)
5). \(\dfrac{x^2}{4}+2xy+4y^2\)
6). \(4x^2+4xy+y^2\)
7). \(\dfrac{1}{9}x^2-\dfrac{2}{3}x+1\)
8). \(x^2-x+\dfrac{1}{4}\)
9). \(x^2+2x+1\)
10). \(-y^2+2yz-z^2\)
11). \(4x^2-12xy+9y^2\)
12) \(-4x^2+2x-\dfrac{1}{4}\)
13). \(x^2+10x+25\)
14) \(x^2+8x+16\)
15). \(x^2-6x+9\)
16). \(4x^2+12x+9\)
17). \(4x^2+20x^2+25\)
18). \(-9x^4+12x^2y^2-4y^4\)
19). \(x^{10}-4x^8+4x^6\)
Phan tich cac da thuc sau thanh nhan tu:
a, -4x2+4x-1
b,(2x+1)2-4(x-1)2
c,(2x+y)2-4x2+12x-9
d, (x+1)2-4(x+1)y2+4y4