\(\dfrac{4}{x+3}=\dfrac{2}{x-1}\left(x\ne-3;x\ne1\right)\)
suy ra: \(4\left(x-1\right)=2\left(x+3\right)\\ < =>4x-4=2x+6\\ < =>4x-2x=6+4\\ < =>2x=10\\ < =>x=5\left(tm\right)\)
\(\dfrac{4}{x+3}=\dfrac{2}{x-1}\text{ĐKXĐ}:x\ne-3;1\)
\(\Leftrightarrow\dfrac{4\left(x-1\right)}{\left(x+3\right)\left(x-1\right)}=\dfrac{2\left(x+3\right)}{\left(x+3\right)\left(x-1\right)}MTC:\left(x+3\right)\left(x-1\right)\)
\(\Rightarrow4x-4=2x+6\)
\(\Leftrightarrow4x-4-2x-6=0\)
\(\Leftrightarrow2x-10=0\)
\(\Leftrightarrow2x=10\)
\(\Leftrightarrow x=5\left(\text{nhận}\right)\)
\(\text{Vậy phương trình có tập nghiệm là }S=\left\{5\right\}\)
ĐKXĐ: `x+3\ne0=>x\ne-3` ; `x-1\ne0=>x\ne1`
\(\dfrac{4}{x+3}=\dfrac{2}{x-1}\\ \Leftrightarrow4\left(x-1\right)=2\left(x+3\right)\\ \Leftrightarrow4x-4=2x+6\\ \Leftrightarrow4x-2x=6+4\\ \Leftrightarrow2x=10\\ \Leftrightarrow x=5\left(tm\right)\)
`4/{x+3}=2/{x-1}` `(đk: x≠-3; x≠1)`
`<=>4.(x-1)=2.(x+3)`
`<=>4x-4=2x+6`
`<=>4x-2x=4+6`
`<=>2x=10`
`<=>5`
`4/{x+3}=2/{x-1}` `(đk: x≠-3; x≠1)`
`<=>4.(x-1)=2.(x+3)`
`<=>4x-4=2x+6`
`<=>4x-2x=4+6`
`<=>2x=10`
`<=>5(tmđk)`
