Question

X+3 phần x-2 bằng 4

Answer 1

\(\dfrac{x+3}{x-2}=4\left(dkxd:x\ne2\right)\)

Suy ra :

\(x+3=4\left(x-2\right)\)

\(\Rightarrow x+3=4x-8\)

\(\Rightarrow-3x=-11\)

\(\Rightarrow x=\dfrac{11}{3}\left(tmdk\right)\)

Vậy \(S=\left\{\dfrac{11}{3}\right\}\)

Answer 2

\(\dfrac{x+3}{x-2}=4\text{ĐKXĐ:}x\ne2\)

\(\Leftrightarrow\dfrac{x+3}{x-2}=\dfrac{4\left(x-2\right)}{x-2}MTC:x-2\)

\(\Rightarrow x+3=4x-8\)

\(\Leftrightarrow x+3-4x+8=0\)

\(\Leftrightarrow11-3x=0\)

\(\Leftrightarrow3x=11\)

\(\Leftrightarrow x=\dfrac{11}{3}\)

\(\text{Vậy phương trình có tập nghiệm là }S=\left\{\dfrac{11}{3}\right\}\)