\(\left|3-2x\right|-3=-\left(-3\right)\)
\(\Leftrightarrow\left|3-2x\right|-3=3\)
\(\Leftrightarrow\left|3-2x\right|=6\)
\(\Leftrightarrow\left[{}\begin{matrix}3-2x=6\\3-2x=-6\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=-3\\2x=9\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{3}{2}\\x=\dfrac{9}{2}\end{matrix}\right.\)
Vậy ..
\(\left|3-2x\right|-3=-\left(-3\right)\)
=>\(\left|3-2x\right|=6\)
Xét \(x\ge\dfrac{3}{2}\Rightarrow\left|3-2x\right|=2x-3\)
Do đó:\(2x-3=6\)
=>2x=9
=>\(x=\dfrac{9}{2}\left(chọn\right)\)
Xét \(x>\dfrac{3}{2}\Rightarrow\left|3-2x\right|=3-2x\)
Do đó:\(3-2x=6\)
=>\(-2x=-3\)
=>\(x=\dfrac{3}{2}\left(loại\right)\)
Vậy...
