\(\left|2x+3\right|+2x=-4\left(đk:x\le-2\left(i\right)\right)\)
\(\Leftrightarrow\left|2x+3\right|=-4-2x\)
\(\Leftrightarrow2x+3=4+2x\)( do (i))
\(\Leftrightarrow3=4\left(VLý\right)\)
Vậy \(S=\varnothing\)
1/Tìm x,biết:
a/|2x-5|=4
b/1/3-|5/4-2x|=1/4
c/2×|2x-3|=1/2
a) |x-1/3|=11/5 b)2|2x-3|=1/2
c)2|3x-1|+1=5 d)3/2+4/5|x-3/4|=7/4
e)|2x-5|=4 f)|x/2-1|=3
Tìm x ; y :
a , / 2x-6 / + / x + 3 / = 8
b , / 2x - 1 / + 2x - 5 / = 4
c , / x + 1 / + / x + 2 / + / x + 3 / + / x + 4 / = 5x - 1
Giúp em với ???
Tìm x:
a) |-3x + 4| + |x - 7| - x + 5 = 0
b) |-x+5| + |2x - 3| - |4x+7| = 0
c) |-x + 2| - |2x+4| - |x+3| - 2x + 1 = 0
~Pleaseee helppp meeeee!!!!
a)|-x+2/5|+1/2=3,5 b)21/5+3:|x/4-2/3|=6
c)7,5-3|5-2x|=-4,5 d)1/3-|5/4-2x|=1/4
e)21/5+3:|x/4-2/3|=6
a)|-x+2/5|+1/2=3,5 b)21/5+3:|x/4-2/3|=6
c)7,5-3|5-2x|=-4,5 d)1/3-|5/4-2x|=1/4
e)21/5+3:|x/4-2/3|=6
a) (2x-4)x+1=(2x-4)x+5
b) (x-3)x+4=(x-3)x+5
c) |x-1|>2
d)| 3+2x|< hoặc= 5
tìm x
Tìm x, biết:
a, \(|2x-3|-\dfrac{5}{2}=\dfrac{1}{3}\)
b, \(|x-1|+3x=1\)
c, \(|5x-3|-x=7\)
d, \(|2x+1|+|x+8|=4x\)
e, \(|3x+2|+|4x+3|=2x-4\)
f, \(|2x-4|+|8-4x|=15\)
g, \(|x^2-2x|=x\)
Tìm x, theo 3 cách:
a) x+1/3=3/6
b) 2x+1/3=3/6
c) 2x-1/4=3/8
