a) x + \(\dfrac{1}{3}=\dfrac{3}{6}\)
x = \(\dfrac{3}{6}-\dfrac{1}{3}\)
x = \(\dfrac{1}{6}\)
b) 2x + \(\dfrac{1}{3}=\dfrac{3}{6}\)
2x = \(\dfrac{1}{6}\)
x = \(\dfrac{1}{12}\)
c ) 2x - \(\dfrac{1}{4}=\dfrac{3}{8}\)
2x = \(\dfrac{5}{8}\)
x = \(\dfrac{5}{16}\)