\(\Leftrightarrow12x^2-12x+20-10x+17=0\)
\(\Leftrightarrow12x^2-22x+37=0\)
\(\text{Δ}=\left(-22\right)^2-4\cdot12\cdot37=-1292< 0\)
Do đó: Phương trình vô nghiệm
Tìm x:
1/3x(\(-\dfrac{4}{3}\)x+1)-4x(x-2)=10
2/5(x2-3x+1)+x(1-5x)=x-2
3/12x2-4x(3x-5)=10x-17
4/4x2-2x+3-4x(x-5)=7x-3
5/-3(x-5)+5(x-1)+3x2=4-x
3x2 + ( -9x ) + 10x = 4 + 15
Tìm x , biết :
a) ( 3x -1 ) (2x+7) - ( x +1) (6x-5 ) = 16
b) ( 10x +9 )x - ( 5x -1 ) (2x+3 )= 8
c) ( 3x - 5 ) ( 7- 5x ) + ( 5x +2 )( 3x-2 ) -2 = 0
d) x(x + 1) ( x+6 ) - x3 = 5x
Tìm x biết : a.3x.(x+1)-2x.(x+20=-1-x
b.(3x-1).(2x+7)-(x+1).(6x-5)=16
c.(10x+9).x-(5x-1).(2x+3)=8
😭😭😭🌚🌚🌚😞😞😞
1. x+2/x-2-1/x=2/x(x-2)
2. 5x +2(x-2)=17
3. x+3x+2/2=1-5x/6
4. x^2 . -16 =3(x-4)
5. x/x-1-x+1/2x+3=1+4x/(x-1)(2x+3)
6. 3x+1=7x-11
7. (x-1)(3x+2)=0
8. 3x-2=-14
9. (4x-2)(3x+5)=0
10. 2x+1/3-7x+5/15=x-2/5
(3x-2)(2x-1)+(x+1)(5-6x)=-17
tính
a. (5x-y)*(x^2-xy+1)
b. (3x^2+10x-1)*(3x+1)
Tìm x :
3x2 - 9x + 10x = 19
Bài 1:Rút gọn:
a,(x+2)(x2+4x+4)-(x-2)(x2-4x-4)-12x2-x
b,(x-2)(x+2)(x+3)-(x+1)(x2-x+1)
Ai làm đúng và nhanh giúp, mình tick liền cho ạ
