a/ Gọi \(D\left(a;0\right)\) \(\Rightarrow\left\{{}\begin{matrix}\overrightarrow{AB}=\left(-9;3\right)\\\overrightarrow{AD}=\left(a-6;-3\right)\end{matrix}\right.\)
Do A; B; D thẳng hàng \(\Leftrightarrow\frac{a-6}{-9}=\frac{-3}{3}\Rightarrow a=15\) \(\Rightarrow D\left(15;0\right)\)
b/ \(\overrightarrow{AB}=\left(-1;5\right);\) \(\overrightarrow{AD}=\left(-2;10\right)\)
\(\Rightarrow\overrightarrow{AD}=2\overrightarrow{AB}\Rightarrow A,B,D\) thẳng hàng