Có: \(3x=2y=4z\Rightarrow\dfrac{x}{\dfrac{1}{3}}=\dfrac{y}{\dfrac{1}{2}}=\dfrac{z}{\dfrac{1}{4}}\)
Và x + y + z = 26
Áp dụng t/c của dãy tỉ số = nhau có:
\(\dfrac{x}{\dfrac{1}{3}}=\dfrac{y}{\dfrac{1}{2}}=\dfrac{z}{\dfrac{1}{4}}=\dfrac{x+y+z}{\dfrac{1}{3}+\dfrac{1}{2}+\dfrac{1}{4}}=\dfrac{26}{9}\)
=> \(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{26}{9}\cdot\dfrac{1}{3}=\dfrac{26}{27}\\y=\dfrac{26}{9}\cdot\dfrac{1}{2}=\dfrac{13}{9}\\z=\dfrac{26}{9}\cdot\dfrac{1}{4}=\dfrac{13}{18}\end{matrix}\right.\)
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