Question

Answer 1

k

\(10^{x+1}=1000\\ \Rightarrow10^{x+1}=10^3\\ \Rightarrow x+1=3\\ \Rightarrow x=2\)

h

\(3^4.3^{x-2}=3^{10}\\ \Rightarrow3^{x-2}=3^{10}:3^4=3^6\\ \Rightarrow x-2=6\\ \Rightarrow x=8\)

i

\(2^x+2^{x+1}=96\\ \Rightarrow2^x+2^x.2=96\\ \Rightarrow2^x\left(1+2\right)=96\\ \Rightarrow2^x=\dfrac{96}{3}=32\\ \Rightarrow2^x=2^5\\ \Rightarrow x=5\)

Answer 2

k: =>x+1=3

=>x=2

h: =>3^x-2=3^6

=>x-2=6

=>x=8

i: =>2^x*3=96

=>2^x=32

=>x=5

Answer 3

`10^(x+1)=1000`

`=> 10^(x+1)=10^3`

`=> x+1=3`

`=>x=2`

Vậy `x=2`

`3^4 . 3^(x-2)= 3^10`

 `=>    3^(x-2) = 3^10 : 3^4`

`=>    3^(x-2)  = 3^6`

`=>    x-2        = 6`

`=>    x           = 6 +2 `

`=>    x          = 8`

Vậy `x=8`

`2^x + 2^(x+1) = 96`

`=> 2^x + 2^x * 2 = 96`

`=> 2^x*(2+1)      = 96`

`=> 2^x * 3          = 96`

`=> 2^x                = 96 : 3`

`=> 2^x                = 32`

`=> x                    =2^5`

Vậy `x = 5`