Question

Answer 1

Bài 3: 

a: \(=\dfrac{\left(x+1\right)^2}{x^2}:\left(\dfrac{x^2+1}{x^2}+\dfrac{2}{x+1}\cdot\dfrac{x+1}{x}\right)\)

\(=\dfrac{\left(x+1\right)^2}{x^2}:\dfrac{x^2+1+2x}{x^2}=1\)

b: \(=\dfrac{x}{x-3}-\dfrac{x\left(x+3\right)}{2x+3}\cdot\left(\dfrac{x+3}{x\left(x-3\right)}-\dfrac{x}{\left(x-3\right)\left(x+3\right)}\right)\)

\(=\dfrac{x}{x-3}-\dfrac{x\left(x+3\right)}{2x+3}\cdot\dfrac{x^2+6x+9-x^2-3x}{x\left(x-3\right)\left(x+3\right)}\)

\(=\dfrac{2x^2+3x}{\left(2x+3\right)\left(x-3\right)}-\dfrac{3x+9}{\left(x-3\right)\left(2x+3\right)}\)

\(=\dfrac{2x^2-9}{\left(2x+3\right)\left(x-3\right)}\)