a) \(1-\left|x+1\right|=\dfrac{3}{5}\\ \Rightarrow\left|x+1\right|=\dfrac{2}{5}\\ \Rightarrow\left[{}\begin{matrix}x+1=-\dfrac{2}{5}\\x+1=\dfrac{2}{5}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{7}{5}\\x=-\dfrac{3}{5}\end{matrix}\right.\)
b) \(\left(x-\dfrac{1}{3}\right)^2=\dfrac{1}{9}\\ \Rightarrow\left[{}\begin{matrix}x-\dfrac{1}{3}=-\dfrac{1}{9}\\x-\dfrac{1}{3}=\dfrac{1}{9}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{2}{9}\\x=\dfrac{4}{9}\end{matrix}\right.\)
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