Ta có: \(\tan a=2\)
=>\(\frac{\sin a}{cosa}=2\)
=>\(\sin a=2\cdot cosa\)
\(1+\tan^2a=\frac{1}{cos^2a}\)
=>\(\frac{1}{cos^2a}=1+4=5\)
=>\(cos^2a=\frac15\)
=>\(\sin^2a=\frac45\)
\(A=\sin^2a+2\cdot\sin a\cdot cosa-3\cdot cos^2a\)
\(=\left(2\cdot cosa\right)^2+2\cdot2\cdot cosa\cdot cosa-3\cdot cos^2a\)
\(=4\cdot cos^2a+4\cdot cos^2a-3\cdot cos^2a=5\cdot cos^2a=5\cdot\frac15=1\)

