Question

Answer 1

`2^{2}.16>=2^{x}>4^{2}`

`->2^{2}.2^{4}>=2^{x}>(2^{2})^{2}`

`->2^{6}>=2^{x}>2^{4}`

`->6>=x>4`

 

Answer 2

Nếu đề cho `x` nguyên

`->x\in{5;6}`

Answer 3

x = 5 hoặc 6

Answer 4

\(2^2.16\ge2^x>4^2\)

\(2^2.2^4\ge2^x>\left(2^2\right)^2\)

\(2^6\ge2^x>2^4\Rightarrow x\in\left\{6;5\right\}\)

Answer 5

2². 2⁴ ≥ 2^x > 2⁴

2⁶ ≥ 2^x > 2⁴

=> 6 ≥ x > 4 

=> x = { 5 ; 6 }

Answer 6

\(2^2.16\ge2^x>4^2\)

\(\rightarrow2^2.2^4\ge2^x>4^2\)

\(\rightarrow2^6\ge2^x>4^2\)

\(\rightarrow2^6\ge2^x>\left(2^2\right)^2\)

\(\rightarrow2^6\ge2^x>2^4\)

\(\Rightarrow6\ge x>4\)

\(\Rightarrow x=\left\{6;5\right\}\)

 

Answer 7

Ta có: \(2^2\cdot16\ge2^x>4^2\)

\(\Leftrightarrow2^6\ge2^x>2^4\)

hay \(x\in\left\{5;6\right\}\)